Curvature calculator

For a distance along the surface, this page gives the bulge of the sphere above the straight chord and the drop of the surface below a horizontal line. From an eye height above the surface, it gives the height of a distant object that is below the horizon. Refraction is shown off and on.

Refraction

This is how much the ray bends in the air. Normal, 0.14, is the ordinary optical value, about 1.16 R; Very strong, 0.25, is the same bend as a 4/3 Earth.

From −0.5 up to, but not including, 1.

Drawing

  • Surface
  • Chord, bulge, and drop
  • Line of sight and hidden height
  • Horizontal at the near surface

Sphere, refraction off

Horizon distance
—
Bulge above the chord
—
Drop below the horizontal
—
Hidden height
—

Sphere, refraction on

Horizon distance
—
Bulge above the chord
—
Drop below the horizontal
—
Hidden height
—

Plane

Horizon distance
—
Bulge above the chord
—
Drop below the horizontal
—
Hidden height
—

The globe and a flat Earth

On the sphere, the drop and the bulge grow with distance. Raising the eye moves the horizon outward and reduces the hidden height. With the eye on the surface, the hidden height and the drop are the same number.

A flat-Earth prediction for this page is the plane column. On a plane, a horizontal line stays at one height above the surface, so the bulge, the drop, and the hidden height are zero at every finite distance. Distance still makes an object look smaller. It does not hide a lower slice of it.

The preset “1 statute mile” puts the eye on the surface and turns refraction off. Over one international statute mile the geometric drop is 8.00 inches and the bulge is 2.00 inches. Those are the well-known short-distance figures d² / (2R) and d² / (8R). The page uses the exact expressions below; at one mile the two agree to a hundredth of an inch.

Assumptions

Formulas

The defining constants are a = … and 1/f = …, so the polar radius b is …. The mean radius is (2a + b) / 3.

Horizon distance along the surface, from height h: R · atan2(√(h (2R + h)), R).

With θ = d / R, the drop is R · (1 − cos θ) / cos θ. The bulge is R · (1 − cos(θ / 2)).

Let s be the horizon distance for the eye. If d ≤ s, the hidden height is zero. Otherwise it is the drop at distance d − s, on the same radius.

Sources