Lunar eclipse

Geometry of the shadow cone. The Earth radius is the GRS80 mean radius, …. The Sun is at 1 AU, and the opening distance of the Moon is 384,400 km. The umbra’s radius at the Moon is set beside the Moon’s angular size, so it is plain whether a total eclipse fits in the cone. An eclipse also needs the Moon near a node. This page does not look up the next eclipse and has no lunar ephemeris.

The three distances are the NASA fact-sheet semimajor axis, perigee, and apogee. They are not the distance on a named night.

The cone on the left is a schematic, not to scale. The two circles on the right are the angular radius of the umbra and the angular radius of the Moon, to scale with each other. The brown circle is the Moon.

  • Earth and the umbra
  • Moon

Umbra

Radius at the Moon
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Moon

Angular radius
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Umbra

Angular radius
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What this page shows

The Sun and the Earth fix a cone of shadow. With Re the Earth radius, Rs the solar radius, and Ds the Sun’s distance, the apex lies beyond the Earth at L = Re × Ds / (Rs − Re). In the plane at distance Dm from the Earth’s centre, the umbra’s radius is Re × (L − Dm) / L.

The angular radius is the arctangent of that radius over Dm, and the same for the Moon’s own radius over Dm. When the umbra is the larger of the two, the Moon can sit inside the shadow. That is the geometric room for a total eclipse. It is not a prediction of one.

An eclipse also needs the Moon near a node, so that it passes through the cone rather than above or below it. This page does not look up the next eclipse and has no lunar ephemeris.

Assumptions

Sources